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Anonymous

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Oct 13, 2007, 9:14 am
1+2+3+......+100= ? 
1+2+3+......+100= ?

Can u find an easy method to calculate it? 

   
   

Answers  (4)


sumesh kumar
Oct 19, 2007,1:29 am
sum of n consequetive terms=(n*(n+1))/2
<br>1+2+3...+100=(100*101)/2
<br>
<br> =5050

 
 


sumesh kumar
Dec 18, 2007,7:02 am
1+100=101
<br>2+99=101
<br>3+98=101 There are fifty pairs like this.So sum is
<br>4+97=101 50*101=5050
<br>........
<br>........
<br>50+51=101

 
 


sumesh kumar
Dec 19, 2007,2:02 am
(n*n+1)/2

 
 


gogokoooo
Jul 12, 2009,6:42 am
923445