Answers (2) |
sumesh kumar
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May 5, 2006,2:25 pm
| just do an inrared spectrophotometry, each will have distinct peak at certain wavenumber that characterizes which is which. |
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sumesh kumar
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May 5, 2006,2:27 pm
Using chemical tests you can distinguish heaxne from the other two by treating each with 1 equivalent of Br2. For hexane the reaction mixture will remain coloured, for the other two the bromine will add electrophilically across the double bonds, removing the bromine from the solution and hence the solutions become colourless.You have now identified hexane.
<br>The other two are a little more tricky, however adding H2O across the double and triple bond will create an alcohol for cyclohexene and a ketone with hex-1-yne. The alcohol can be tested for using the Lucas reagent, whereas the ketone can be test for using 2,4-dinitrophenylhydrazine, which will form an orange/yellow crystalline solid known as an imine with a ketone/aldehyde. The formation of an imine from a hydrazine and a ketone is simply loss of water. (nucleophilic attack of the hydrazine onto the ketone, proton transfer and a trans elimination of water.
<br>You should now be able to identify the other two by the positive/negative results on each of the two chemical tests described.Markovnikoffs rule explains the mechanism and regioselectivity of the addition of water across double/triple bonds. |
 
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